Radial Mode, Gravity, and Forces

  • Rconover
    21st Jan 2011 Member 0 Permalink
    This thread was created for the observation of gravity in the powdertoy of Radial Mode. Radial mode is when gravity is focused on the center of the screen. I created a "core" of STNE, and then I created a small "moon" of STNE with Thunder on the tangent side of the stone Moon. By allowing the simulation to run, the thunder explodes the moon and particles fly everywhere, some particles are too slow and they fall to the center. Some particles are too fast and fly off the screen. I have reason to believe that powdertoy's Radial mode is heavily dependent on pressure. Basically, the larger the core and the closer the particles to the core, the more pressure that is reflected off of the core, causing the particles to fly outward faster, but once the core is deleted, the particles rush inward while still retaining it's orbit and form this perfect orbital.


    This is a simulation of 4 particles in a very slight elliptical orbit in fire display. O represents the center

    http://i355.photobucket.com/albums/r465/superKoolpictures/PowdertoyGravitysim.jpg

    This next picture is the same simulation in persistent mode to prove the orbit.

    http://i355.photobucket.com/albums/r465/superKoolpictures/PowdertoyGravitysim2.jpg

    In this grid, the radius of the orbit is 3.5 units.

    The time it takes for one particle to go around once was measured in the frames per second, in this simulation I have a consistent 37.

    I stopped the simulation and used the F button to advance the frames one at a time. the number of frames it took to go around is 59.5

    So, basically it takes 1.6081 seconds to go around because 59.5/37 is this.

    So now that we have time, lets calculate for the circumference so we can calculate Centripetal Acceleration.

    A=V^2/t where A is the acceleration and V is the velocity.

    V is equal to 2(pi)r/t where t is seconds

    2(pi)3.5 = 21.9911

    21.9911/1.6081

    simplify this to become

    13.089/s

    So now lets go back to the Acceleration formula

    A = (13.089)^2/1.6081

    A= 106.537

    the centripetal Acceleration of this simulation is 106.537

    I will attempt to Calculate the Mass so I can calculate for Force so I can calculate for official gravity
    -------------------------------------
    What is very exciting about this is that when I add particles to the simulation WITHOUT giving them force, they should fall straight to the center right? lol NO!
    Additional particles will curve to the orbit, although the mass of the particle added will disrupt the elipse, the added particle will flow into the stream as if some sort of pressure series is going on, take a look here:

    http://i355.photobucket.com/albums/r465/superKoolpictures/PowdertoyGravitysim3.jpg

    Notice the BIZR particle, it is the bright colored particle. the particle starts at the START sign

    Notice that the slope of the line changes, it FLOWS into the orbit, proving that there is some sort of pressure going on forcing it to move in such a way.
  • jacobrb
    21st Jan 2011 Member 0 Permalink
    um... why did you make a post to make me feel retarted?
  • Rconover
    21st Jan 2011 Member 0 Permalink
    @jacobrb
    I didn't, this was to have some laws of gravity in TPT, what will be my next challenge is to calculate what is the ACTUAL value of gravity
  • Rconover
    21st Jan 2011 Member 0 Permalink
    TL;DR

    When creating an orbital, if the core is close enough to the orbiting particles, the mass of the core will repel the pressure waves created by the particles and the particles will be pushed outward and eventually fly off the screen.

    A core too small and the particles without the proper speed for it's pressure will fall to the center rapidly and the inertia will cause them to collide because they passed near the center too fast and eventually collide with each other.

    Simple: too slow, the particle will fall to the center and become part of the core.

    Too fast, the particle will fly outward beyond the screen and disappear.

    Particles with a good speed to maintain orbit but too close to the core surface will repel outward and disappear

    Particles with a good speed to maintain orbit, but too far from the core, will fall inward, usually too fast and become part of the core.
  • cracker64
    21st Jan 2011 Developer 0 Permalink
    particles moving causes pressure, so anything added after you have an orbit will be affected by it.
    and yes, you did a lot of work on this lol.
    things in powder toy don't have mass, they just use an imaginary gravity variable that says how fast it moves down.
  • Rconover
    21st Jan 2011 Member 0 Permalink
    hmm

    then I will define mass as imaginary through the square root of -1

    will post results

    PS, how do I make a square root symbol in the forums using key commands?
  • hugoRawr
    21st Jan 2011 Member 0 Permalink
    @Rconover
    shift + 6

    also: math for the win
  • HarmonicFarts
    21st Jan 2011 Member 0 Permalink
    Rconover:
    PS, how do I make a square root symbol in the forums using key commands?

    Just use character map. Its a program on your computer.
  • Rconover
    21st Jan 2011 Member 0 Permalink
    @HarmonicFarts
    I know that, I was just hoping for some sort of hot key
    @hugoRawr
    thats the exponent karot, if I wanted the square root of something I would have to put it as #^1/2
  • Made2Shred
    21st Jan 2011 Member 0 Permalink
    nice calculations